Free Apple Music subscription not received for new Apple Watch and AirPods

i buy apple wach ultra 3 and AirPods 3pro last month and I should receive free Apple Music app for 3 months like averyobe who received new device but unfortunately - I didn’t receive any , is it because I used to use it 6 months before ? If so why ? Bother web on official side there is info Avery one should have it for new device ???



[Re-Titled by Moderator]

Original Title: Apple Music free subscription

Apple Watch Ultra 3, watchOS 26

Posted on Nov 7, 2025 9:03 AM

Reply
Question marked as Top-ranking reply

Posted on Nov 7, 2025 9:10 AM

The offer is for new subscribers only. If you were previously subscribed to Apple Music, you are not a new subscriber. With any subscription to Apple Music it comes with a Free Trial and a Free Trial cannot be used more than once. The terms of the offer are available here:

https://www.apple.com/promo/pdf/US_T_Apple_Music_Promo_Terms_3_month.pdf


If you saw an offer that said something different or did not have a link to those terms for you to review, then post what that is.

1 reply
Question marked as Top-ranking reply

Nov 7, 2025 9:10 AM in response to Marynarz

The offer is for new subscribers only. If you were previously subscribed to Apple Music, you are not a new subscriber. With any subscription to Apple Music it comes with a Free Trial and a Free Trial cannot be used more than once. The terms of the offer are available here:

https://www.apple.com/promo/pdf/US_T_Apple_Music_Promo_Terms_3_month.pdf


If you saw an offer that said something different or did not have a link to those terms for you to review, then post what that is.

This thread has been closed by the system or the community team. You may vote for any posts you find helpful, or search the Community for additional answers.

Free Apple Music subscription not received for new Apple Watch and AirPods

Welcome to Apple Support Community
A forum where Apple customers help each other with their products. Get started with your Apple Account.